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12112213131000 = 2332536143375087
BaseRepresentation
bin1011000001000001100000…
…1010010011111011111000
31120212220201221212210011100
42300100120022103323320
53041421303030143000
641432135054531400
72360035634621643
oct260203012237370
946786657783140
1012112213131000
11394a840602aa4
121437517806b60
1369b23b567b58
142dc33ca9aa5a
151600ee47aa00
hexb0418293ef8

12112213131000 has 384 divisors, whose sum is σ = 41628192053760. Its totient is φ = 3175617024000.

The previous prime is 12112213130993. The next prime is 12112213131023. The reversal of 12112213131000 is 13131221121.

12112213131000 is a `hidden beast` number, since 121 + 1 + 221 + 313 + 10 + 0 + 0 = 666.

It is a super-2 number, since 2×121122131310002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2381010457 + ... + 2381015543.

It is an arithmetic number, because the mean of its divisors is an integer number (108406750140).

Almost surely, 212112213131000 is an apocalyptic number.

12112213131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12112213131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20814096026880).

12112213131000 is an abundant number, since it is smaller than the sum of its proper divisors (29515978922760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12112213131000 is a wasteful number, since it uses less digits than its factorization.

12112213131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9512 (or 9495 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 12112213131000 its reverse (13131221121), we get a palindrome (12125344352121).

The spelling of 12112213131000 in words is "twelve trillion, one hundred twelve billion, two hundred thirteen million, one hundred thirty-one thousand".