Base | Representation |
---|---|
bin | 10001101000000010011… |
… | …011001000010110001111 |
3 | 11021210101002211112020212 |
4 | 101220002123020112033 |
5 | 124321040142201413 |
6 | 2324232155033035 |
7 | 153336124255115 |
oct | 21500233102617 |
9 | 4253332745225 |
10 | 1211221443983 |
11 | 427748a24041 |
12 | 1768ab73b77b |
13 | 8a2aa3670a5 |
14 | 428a299dab5 |
15 | 2178ee1cca8 |
hex | 11a026c858f |
1211221443983 has 2 divisors, whose sum is σ = 1211221443984. Its totient is φ = 1211221443982.
The previous prime is 1211221443977. The next prime is 1211221444009. The reversal of 1211221443983 is 3893441221121.
It is a weak prime.
It is an emirp because it is prime and its reverse (3893441221121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1211221443983 - 226 = 1211154335119 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1211221443983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211221443083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605610721991 + 605610721992.
It is an arithmetic number, because the mean of its divisors is an integer number (605610721992).
Almost surely, 21211221443983 is an apocalyptic number.
1211221443983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211221443983 is an equidigital number, since it uses as much as digits as its factorization.
1211221443983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 41.
The spelling of 1211221443983 in words is "one trillion, two hundred eleven billion, two hundred twenty-one million, four hundred forty-three thousand, nine hundred eighty-three".
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