Base | Representation |
---|---|
bin | 1011000001000001100010… |
… | …1100100111000010001111 |
3 | 1120212220202120210120200001 |
4 | 2300100120230213002033 |
5 | 3041421312330402002 |
6 | 41432140015345131 |
7 | 2360036104220101 |
oct | 260203054470217 |
9 | 46786676716601 |
10 | 12112222122127 |
11 | 394a845694186 |
12 | 143751a8221a7 |
13 | 69b24039544a |
14 | 2dc33dd5b571 |
15 | 160100154a87 |
hex | b0418b2708f |
12112222122127 has 2 divisors, whose sum is σ = 12112222122128. Its totient is φ = 12112222122126.
The previous prime is 12112222122107. The next prime is 12112222122139. The reversal of 12112222122127 is 72122122221121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12112222122127 - 235 = 12077862383759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12112222122095 and 12112222122104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12112222122107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056111061063 + 6056111061064.
It is an arithmetic number, because the mean of its divisors is an integer number (6056111061064).
Almost surely, 212112222122127 is an apocalyptic number.
12112222122127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112222122127 is an equidigital number, since it uses as much as digits as its factorization.
12112222122127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1792, while the sum is 28.
Adding to 12112222122127 its reverse (72122122221121), we get a palindrome (84234344343248).
The spelling of 12112222122127 in words is "twelve trillion, one hundred twelve billion, two hundred twenty-two million, one hundred twenty-two thousand, one hundred twenty-seven".
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