Base | Representation |
---|---|
bin | 1011000001000001111000… |
… | …0100010110100011101011 |
3 | 1120212220222212100122102002 |
4 | 2300100132010112203223 |
5 | 3041422003412412141 |
6 | 41432152555001215 |
7 | 2360041250151434 |
oct | 260203604264353 |
9 | 46786885318362 |
10 | 12112312232171 |
11 | 394a891540198 |
12 | 1437544a3920b |
13 | 69b255c554b8 |
14 | 2dc34bcd648b |
15 | 160108003e9b |
hex | b041e1168eb |
12112312232171 has 2 divisors, whose sum is σ = 12112312232172. Its totient is φ = 12112312232170.
The previous prime is 12112312232081. The next prime is 12112312232173. The reversal of 12112312232171 is 17123221321121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12112312232171 is a prime.
Together with 12112312232173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12112312232173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056156116085 + 6056156116086.
It is an arithmetic number, because the mean of its divisors is an integer number (6056156116086).
Almost surely, 212112312232171 is an apocalyptic number.
12112312232171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112312232171 is an equidigital number, since it uses as much as digits as its factorization.
12112312232171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2016, while the sum is 29.
Adding to 12112312232171 its reverse (17123221321121), we get a palindrome (29235533553292).
The spelling of 12112312232171 in words is "twelve trillion, one hundred twelve billion, three hundred twelve million, two hundred thirty-two thousand, one hundred seventy-one".
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