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121123131233183 is a prime number
BaseRepresentation
bin11011100010100100101101…
…001101100001001110011111
3120212212020222021100012100022
4123202210231031201032133
5111333440133043430213
61105335110501022355
734340600051146262
oct3342445515411637
9525766867305308
10121123131233183
11356590389a9042
12117025836b49bb
135277b29521c71
1421ca568626cd9
15e00a55bda308
hex6e292d36139f

121123131233183 has 2 divisors, whose sum is σ = 121123131233184. Its totient is φ = 121123131233182.

The previous prime is 121123131233099. The next prime is 121123131233267. The reversal of 121123131233183 is 381332131321121.

It is a balanced prime because it is at equal distance from previous prime (121123131233099) and next prime (121123131233267).

It is a cyclic number.

It is not a de Polignac number, because 121123131233183 - 226 = 121123064124319 is a prime.

It is a super-2 number, since 2×1211231312331832 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121123131233483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60561565616591 + 60561565616592.

It is an arithmetic number, because the mean of its divisors is an integer number (60561565616592).

Almost surely, 2121123131233183 is an apocalyptic number.

121123131233183 is a deficient number, since it is larger than the sum of its proper divisors (1).

121123131233183 is an equidigital number, since it uses as much as digits as its factorization.

121123131233183 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 35.

The spelling of 121123131233183 in words is "one hundred twenty-one trillion, one hundred twenty-three billion, one hundred thirty-one million, two hundred thirty-three thousand, one hundred eighty-three".