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1211243300101 is a prime number
BaseRepresentation
bin10001101000000011101…
…110100000010100000101
311021210102121221221012201
4101220003232200110011
5124321111241100401
62324234255314501
7153336511114432
oct21500356402405
94253377857181
101211243300101
1142775a2a194a
121768b6b1ba31
138a2b1a4a2c3
14428a584cb89
1521791cd8b01
hex11a03ba0505

1211243300101 has 2 divisors, whose sum is σ = 1211243300102. Its totient is φ = 1211243300100.

The previous prime is 1211243300039. The next prime is 1211243300143. The reversal of 1211243300101 is 1010033421121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 783986284900 + 427257015201 = 885430^2 + 653649^2 .

It is an emirp because it is prime and its reverse (1010033421121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1211243300101 - 229 = 1210706429189 is a prime.

It is a super-2 number, since 2×12112433001012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211243300171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605621650050 + 605621650051.

It is an arithmetic number, because the mean of its divisors is an integer number (605621650051).

Almost surely, 21211243300101 is an apocalyptic number.

It is an amenable number.

1211243300101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211243300101 is an equidigital number, since it uses as much as digits as its factorization.

1211243300101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1211243300101 its reverse (1010033421121), we get a palindrome (2221276721222).

The spelling of 1211243300101 in words is "one trillion, two hundred eleven billion, two hundred forty-three million, three hundred thousand, one hundred one".