Base | Representation |
---|---|
bin | 10001101000000011101… |
… | …110100000010100101111 |
3 | 11021210102121221221021021 |
4 | 101220003232200110233 |
5 | 124321111241101033 |
6 | 2324234255315011 |
7 | 153336511114522 |
oct | 21500356402457 |
9 | 4253377857237 |
10 | 1211243300143 |
11 | 42775a2a1988 |
12 | 1768b6b1ba67 |
13 | 8a2b1a4a326 |
14 | 428a584cbb9 |
15 | 21791cd8b2d |
hex | 11a03ba052f |
1211243300143 has 2 divisors, whose sum is σ = 1211243300144. Its totient is φ = 1211243300142.
The previous prime is 1211243300101. The next prime is 1211243300171. The reversal of 1211243300143 is 3410033421121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211243300143 is a prime.
It is a super-2 number, since 2×12112433001432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211243390143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605621650071 + 605621650072.
It is an arithmetic number, because the mean of its divisors is an integer number (605621650072).
Almost surely, 21211243300143 is an apocalyptic number.
1211243300143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211243300143 is an equidigital number, since it uses as much as digits as its factorization.
1211243300143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1211243300143 its reverse (3410033421121), we get a palindrome (4621276721264).
The spelling of 1211243300143 in words is "one trillion, two hundred eleven billion, two hundred forty-three million, three hundred thousand, one hundred forty-three".
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