Base | Representation |
---|---|
bin | 10001101000000111000… |
… | …111001110011000010101 |
3 | 11021210120120212021100011 |
4 | 101220013013032120111 |
5 | 124321220312040033 |
6 | 2324244045120221 |
7 | 153341101032454 |
oct | 21500707163025 |
9 | 4253516767304 |
10 | 1211300111893 |
11 | 427789375443 |
12 | 176911b59071 |
13 | 8a2c074c051 |
14 | 428ad1dab9b |
15 | 21796cabccd |
hex | 11a071ce615 |
1211300111893 has 2 divisors, whose sum is σ = 1211300111894. Its totient is φ = 1211300111892.
The previous prime is 1211300111891. The next prime is 1211300111897. The reversal of 1211300111893 is 3981110031121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 849674681284 + 361625430609 = 921778^2 + 601353^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211300111893 - 21 = 1211300111891 is a prime.
It is a super-2 number, since 2×12113001118932 (a number of 25 digits) contains 22 as substring.
Together with 1211300111891, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211300111891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605650055946 + 605650055947.
It is an arithmetic number, because the mean of its divisors is an integer number (605650055947).
Almost surely, 21211300111893 is an apocalyptic number.
It is an amenable number.
1211300111893 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211300111893 is an equidigital number, since it uses as much as digits as its factorization.
1211300111893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 31.
The spelling of 1211300111893 in words is "one trillion, two hundred eleven billion, three hundred million, one hundred eleven thousand, eight hundred ninety-three".
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