1211300112149 has 2 divisors, whose sum is σ = 1211300112150. Its totient is φ = 1211300112148.

The previous prime is 1211300112119. The next prime is 1211300112161. The reversal of 1211300112149 is 9412110031121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1022950188100 + 188349924049 = 1011410^2 + 433993^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211300112149 - 2⁸ = 1211300111893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211300112119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605650056074 + 605650056075.

It is an arithmetic number, because the mean of its divisors is an integer number (605650056075).

Almost surely, 2^{1211300112149} is an apocalyptic number.

It is an amenable number.

1211300112149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211300112149 is an equidigital number, since it uses as much as digits as its factorization.

1211300112149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 26.

The spelling of 1211300112149 in words is "one trillion, two hundred eleven billion, three hundred million, one hundred twelve thousand, one hundred forty-nine".