Base | Representation |
---|---|
bin | 10001101000000111000… |
… | …111001110011111011101 |
3 | 11021210120120212021222001 |
4 | 101220013013032133131 |
5 | 124321220312043344 |
6 | 2324244045122301 |
7 | 153341101034005 |
oct | 21500707163735 |
9 | 4253516767861 |
10 | 1211300112349 |
11 | 427789375818 |
12 | 176911b59391 |
13 | 8a2c074c312 |
14 | 428ad1db005 |
15 | 21796cabed4 |
hex | 11a071ce7dd |
1211300112349 has 2 divisors, whose sum is σ = 1211300112350. Its totient is φ = 1211300112348.
The previous prime is 1211300112307. The next prime is 1211300112403. The reversal of 1211300112349 is 9432110031121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 660115625625 + 551184486724 = 812475^2 + 742418^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211300112349 - 27 = 1211300112221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211300112149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605650056174 + 605650056175.
It is an arithmetic number, because the mean of its divisors is an integer number (605650056175).
Almost surely, 21211300112349 is an apocalyptic number.
It is an amenable number.
1211300112349 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211300112349 is an equidigital number, since it uses as much as digits as its factorization.
1211300112349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
It can be divided in two parts, 12113001 and 12349, that added together give a triangular number (12125350 = T4924).
The spelling of 1211300112349 in words is "one trillion, two hundred eleven billion, three hundred million, one hundred twelve thousand, three hundred forty-nine".
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