1211300301031 has 2 divisors, whose sum is σ = 1211300301032. Its totient is φ = 1211300301030.

The previous prime is 1211300300989. The next prime is 1211300301047. The reversal of 1211300301031 is 1301030031121.

It is an a-pointer prime, because the next prime (1211300301047) can be obtained adding 1211300301031 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1211300301031 is a prime.

It is a super-2 number, since 2×1211300301031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211300300996 and 1211300301014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211300301061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605650150515 + 605650150516.

It is an arithmetic number, because the mean of its divisors is an integer number (605650150516).

Almost surely, 2^{1211300301031} is an apocalyptic number.

1211300301031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211300301031 is an equidigital number, since it uses as much as digits as its factorization.

1211300301031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1211300301031 its reverse (1301030031121), we get a palindrome (2512330332152).

The spelling of 1211300301031 in words is "one trillion, two hundred eleven billion, three hundred million, three hundred one thousand, thirty-one".