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121130098191647 = 2910627393046009
BaseRepresentation
bin11011100010101011001100…
…011110010110110100011111
3120212212220221210220100122222
4123202223030132112310133
5111334043420114113042
61105342222055055555
734341234516261446
oct3342531436266437
9525786853810588
10121130098191647
1135660a93635056
12117039a89715bb
135278699a296ac
1421caa29a21d5d
15e00d126792d2
hex6e2acc796d1f

121130098191647 has 8 divisors (see below), whose sum is σ = 125318789828400. Its totient is φ = 116942192668224.

The previous prime is 121130098191581. The next prime is 121130098191757. The reversal of 121130098191647 is 746191890031121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121130098191647 - 216 = 121130098126111 is a prime.

It is a super-3 number, since 3×1211300981916473 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121130038191647) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 196214822 + ... + 196831187.

It is an arithmetic number, because the mean of its divisors is an integer number (15664848728550).

Almost surely, 2121130098191647 is an apocalyptic number.

121130098191647 is a deficient number, since it is larger than the sum of its proper divisors (4188691636753).

121130098191647 is a wasteful number, since it uses less digits than its factorization.

121130098191647 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 393056665.

The product of its (nonzero) digits is 653184, while the sum is 53.

The spelling of 121130098191647 in words is "one hundred twenty-one trillion, one hundred thirty billion, ninety-eight million, one hundred ninety-one thousand, six hundred forty-seven".

Divisors: 1 29 10627 308183 393046009 11398334261 4176899937643 121130098191647