Base | Representation |
---|---|
bin | 10001101000000111010… |
… | …011011011101101100111 |
3 | 11021210120210212212101012 |
4 | 101220013103123231213 |
5 | 124321222121442411 |
6 | 2324244241452435 |
7 | 153341140162055 |
oct | 21500723335547 |
9 | 4253523785335 |
10 | 1211303312231 |
11 | 427790160951 |
12 | 17691304111b |
13 | 8a2c12cc93c |
14 | 428ad7d11d5 |
15 | 217971e018b |
hex | 11a074dbb67 |
1211303312231 has 2 divisors, whose sum is σ = 1211303312232. Its totient is φ = 1211303312230.
The previous prime is 1211303312207. The next prime is 1211303312239. The reversal of 1211303312231 is 1322133031121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211303312231 is a prime.
It is a super-2 number, since 2×12113033122312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1211303312197 and 1211303312206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211303312239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605651656115 + 605651656116.
It is an arithmetic number, because the mean of its divisors is an integer number (605651656116).
Almost surely, 21211303312231 is an apocalyptic number.
1211303312231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211303312231 is an equidigital number, since it uses as much as digits as its factorization.
1211303312231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1211303312231 its reverse (1322133031121), we get a palindrome (2533436343352).
The spelling of 1211303312231 in words is "one trillion, two hundred eleven billion, three hundred three million, three hundred twelve thousand, two hundred thirty-one".
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