12113044102141 has 4 divisors (see below), whose sum is σ = 12266373774400. Its totient is φ = 11959714429884.

The previous prime is 12113044102127. The next prime is 12113044102157. The reversal of 12113044102141 is 14120144031121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12113044102141 - 2⁷ = 12113044102013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113044102111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76664836011 + ... + 76664836168.

It is an arithmetic number, because the mean of its divisors is an integer number (3066593443600).

Almost surely, 2^{12113044102141} is an apocalyptic number.

It is an amenable number.

12113044102141 is a deficient number, since it is larger than the sum of its proper divisors (153329672259).

12113044102141 is an equidigital number, since it uses as much as digits as its factorization.

12113044102141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153329672258.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 12113044102141 its reverse (14120144031121), we get a palindrome (26233188133262).

The spelling of 12113044102141 in words is "twelve trillion, one hundred thirteen billion, forty-four million, one hundred two thousand, one hundred forty-one".