12113100030000 has 200 divisors, whose sum is σ = 39109530544128. Its totient is φ = 3229595936000.

The previous prime is 12113100029983. The next prime is 12113100030019. The reversal of 12113100030000 is 3000131121.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 188577889 + ... + 188642111.

Almost surely, 2^{12113100030000} is an apocalyptic number.

12113100030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113100030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19554765272064).

12113100030000 is an abundant number, since it is smaller than the sum of its proper divisors (26996430514128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113100030000 is an equidigital number, since it uses as much as digits as its factorization.

12113100030000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70541 (or 70520 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 12113100030000 its reverse (3000131121), we get a palindrome (12116100161121).

The spelling of 12113100030000 in words is "twelve trillion, one hundred thirteen billion, one hundred million, thirty thousand".