Base | Representation |
---|---|
bin | 111000011001111111… |
… | …0001001001110001011 |
3 | 102120122211101000122221 |
4 | 1300303332021032023 |
5 | 3441034014404003 |
6 | 131351413554511 |
7 | 11515511423260 |
oct | 1606376111613 |
9 | 376584330587 |
10 | 121131013003 |
11 | 4740a331a10 |
12 | 1b586645a37 |
13 | b565606130 |
14 | 5c11639267 |
15 | 323e4157bd |
hex | 1c33f8938b |
121131013003 has 48 divisors (see below), whose sum is σ = 165445491456. Its totient is φ = 85648006080.
The previous prime is 121131013001. The next prime is 121131013037. The reversal of 121131013003 is 300310131121.
It is not a de Polignac number, because 121131013003 - 21 = 121131013001 is a prime.
It is a super-2 number, since 2×1211310130032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (121131013001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3467100 + ... + 3501862.
It is an arithmetic number, because the mean of its divisors is an integer number (3446781072).
Almost surely, 2121131013003 is an apocalyptic number.
121131013003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
121131013003 is a deficient number, since it is larger than the sum of its proper divisors (44314478453).
121131013003 is a wasteful number, since it uses less digits than its factorization.
121131013003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34912 (or 34853 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 121131013003 its reverse (300310131121), we get a palindrome (421441144124).
The spelling of 121131013003 in words is "one hundred twenty-one billion, one hundred thirty-one million, thirteen thousand, three".
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