1211311303133 has 4 divisors (see below), whose sum is σ = 1212409501248. Its totient is φ = 1210213105020.

The previous prime is 1211311303079. The next prime is 1211311303141. The reversal of 1211311303133 is 3313031131121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211311303133 - 2²² = 1211307108829 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1211311303099 and 1211311303108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211311903133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549097403 + ... + 549099608.

It is an arithmetic number, because the mean of its divisors is an integer number (303102375312).

Almost surely, 2^{1211311303133} is an apocalyptic number.

It is an amenable number.

1211311303133 is a deficient number, since it is larger than the sum of its proper divisors (1098198115).

1211311303133 is a wasteful number, since it uses less digits than its factorization.

1211311303133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1098198114.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1211311303133 its reverse (3313031131121), we get a palindrome (4524342434254).

The spelling of 1211311303133 in words is "one trillion, two hundred eleven billion, three hundred eleven million, three hundred three thousand, one hundred thirty-three".