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121132001 is a prime number
BaseRepresentation
bin1110011100001…
…01001111100001
322102221010212102
413032011033201
5222002211001
620004140145
73000414344
oct716051741
9272833772
10121132001
11624152a1
1234697655
131c132253
141213245b
15a97ae6b
hex73853e1

121132001 has 2 divisors, whose sum is σ = 121132002. Its totient is φ = 121132000.

The previous prime is 121131991. The next prime is 121132003. The reversal of 121132001 is 100231121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67256401 + 53875600 = 8201^2 + 7340^2 .

It is an emirp because it is prime and its reverse (100231121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121132001 is a prime.

Together with 121132003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121132003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60566000 + 60566001.

It is an arithmetic number, because the mean of its divisors is an integer number (60566001).

Almost surely, 2121132001 is an apocalyptic number.

It is an amenable number.

121132001 is a deficient number, since it is larger than the sum of its proper divisors (1).

121132001 is an equidigital number, since it uses as much as digits as its factorization.

121132001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 121132001 is about 11005.9984099581. The cubic root of 121132001 is about 494.7885380484.

Adding to 121132001 its reverse (100231121), we get a palindrome (221363122).

The spelling of 121132001 in words is "one hundred twenty-one million, one hundred thirty-two thousand, one".