Base | Representation |
---|---|
bin | 10001101000001000010… |
… | …011001011010000011111 |
3 | 11021210121222022210221021 |
4 | 101220020103023100133 |
5 | 124321240411201142 |
6 | 2324250035545011 |
7 | 153341432205532 |
oct | 21501023132037 |
9 | 4253558283837 |
10 | 1211320022047 |
11 | 427799634213 |
12 | 17691875b167 |
13 | 8a2c49005c5 |
14 | 428b1b00a19 |
15 | 217988e1267 |
hex | 11a084cb41f |
1211320022047 has 2 divisors, whose sum is σ = 1211320022048. Its totient is φ = 1211320022046.
The previous prime is 1211320021981. The next prime is 1211320022083. The reversal of 1211320022047 is 7402200231121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211320022047 - 235 = 1176960283679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211320023047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605660011023 + 605660011024.
It is an arithmetic number, because the mean of its divisors is an integer number (605660011024).
Almost surely, 21211320022047 is an apocalyptic number.
1211320022047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211320022047 is an equidigital number, since it uses as much as digits as its factorization.
1211320022047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1211320022047 its reverse (7402200231121), we get a palindrome (8613520253168).
The spelling of 1211320022047 in words is "one trillion, two hundred eleven billion, three hundred twenty million, twenty-two thousand, forty-seven".
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