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12113201143 is a prime number
BaseRepresentation
bin10110100100000000…
…01100011111110111
31011021012010101010101
423102000030133313
5144301434414033
65321551534531
7606114340141
oct132200143767
934235111111
1012113201143
11515664a33a
12242082a447
1311b074ac54
1482ca87c91
154ad68197d
hex2d200c7f7

12113201143 has 2 divisors, whose sum is σ = 12113201144. Its totient is φ = 12113201142.

The previous prime is 12113201059. The next prime is 12113201167. The reversal of 12113201143 is 34110231121.

12113201143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12113201143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12113201143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113207143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056600571 + 6056600572.

It is an arithmetic number, because the mean of its divisors is an integer number (6056600572).

Almost surely, 212113201143 is an apocalyptic number.

12113201143 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113201143 is an equidigital number, since it uses as much as digits as its factorization.

12113201143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12113201143 its reverse (34110231121), we get a palindrome (46223432264).

The spelling of 12113201143 in words is "twelve billion, one hundred thirteen million, two hundred one thousand, one hundred forty-three".