121132210303 has 4 divisors (see below), whose sum is σ = 130450072648. Its totient is φ = 111814347960.

The previous prime is 121132210289. The next prime is 121132210327. The reversal of 121132210303 is 303012231121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303012231121 = 32377 ⋅9358873.

It is a cyclic number.

It is not a de Polignac number, because 121132210303 - 2⁵ = 121132210271 is a prime.

It is a super-4 number, since 4×121132210303⁴ (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121132210333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4658931153 + ... + 4658931178.

It is an arithmetic number, because the mean of its divisors is an integer number (32612518162).

Almost surely, 2^121132210303 is an apocalyptic number.

121132210303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

121132210303 is a deficient number, since it is larger than the sum of its proper divisors (9317862345).

121132210303 is an equidigital number, since it uses as much as digits as its factorization.

121132210303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9317862344.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 121132210303 its reverse (303012231121), we get a palindrome (424144441424).

The spelling of 121132210303 in words is "one hundred twenty-one billion, one hundred thirty-two million, two hundred ten thousand, three hundred three".