12113241311 has 2 divisors, whose sum is σ = 12113241312. Its totient is φ = 12113241310.

The previous prime is 12113241253. The next prime is 12113241313. The reversal of 12113241311 is 11314231121.

It is a strong prime.

It is an emirp because it is prime and its reverse (11314231121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12113241311 is a prime.

Together with 12113241313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113241313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056620655 + 6056620656.

It is an arithmetic number, because the mean of its divisors is an integer number (6056620656).

Almost surely, 2^12113241311 is an apocalyptic number.

12113241311 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113241311 is an equidigital number, since it uses as much as digits as its factorization.

12113241311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 20.

Adding to 12113241311 its reverse (11314231121), we get a palindrome (23427472432).

The spelling of 12113241311 in words is "twelve billion, one hundred thirteen million, two hundred forty-one thousand, three hundred eleven".