12113251333 has 4 divisors (see below), whose sum is σ = 12504001408. Its totient is φ = 11722501260.

The previous prime is 12113251301. The next prime is 12113251363. The reversal of 12113251333 is 33315231121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33315231121 = 3797 ⋅8774093.

It is a cyclic number.

It is not a de Polignac number, because 12113251333 - 2⁵ = 12113251301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12113251298 and 12113251307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113251363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195374991 + ... + 195375052.

It is an arithmetic number, because the mean of its divisors is an integer number (3126000352).

Almost surely, 2^12113251333 is an apocalyptic number.

It is an amenable number.

12113251333 is a deficient number, since it is larger than the sum of its proper divisors (390750075).

12113251333 is an equidigital number, since it uses as much as digits as its factorization.

12113251333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 390750074.

The product of its digits is 1620, while the sum is 25.

Adding to 12113251333 its reverse (33315231121), we get a palindrome (45428482454).

The spelling of 12113251333 in words is "twelve billion, one hundred thirteen million, two hundred fifty-one thousand, three hundred thirty-three".