Base | Representation |
---|---|
bin | 10001101000001000111… |
… | …101100011101001101011 |
3 | 11021210122202020020221102 |
4 | 101220020331203221223 |
5 | 124321301232211021 |
6 | 2324251114032015 |
7 | 153341625510230 |
oct | 21501075435153 |
9 | 4253582206842 |
10 | 1211331132011 |
11 | 4277a4932300 |
12 | 17692041860b |
13 | 8a2c6cc0450 |
14 | 428b3393787 |
15 | 2179988800b |
hex | 11a08f63a6b |
1211331132011 has 96 divisors (see below), whose sum is σ = 1711548969984. Its totient is φ = 832637203200.
The previous prime is 1211331131987. The next prime is 1211331132013. The reversal of 1211331132011 is 1102311331121.
It is not a de Polignac number, because 1211331132011 - 230 = 1210257390187 is a prime.
It is a super-2 number, since 2×12113311320112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1211331132013) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 489030305 + ... + 489032781.
It is an arithmetic number, because the mean of its divisors is an integer number (17828635104).
Almost surely, 21211331132011 is an apocalyptic number.
1211331132011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1211331132011 is a deficient number, since it is larger than the sum of its proper divisors (500217837973).
1211331132011 is a wasteful number, since it uses less digits than its factorization.
1211331132011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4473 (or 4462 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1211331132011 its reverse (1102311331121), we get a palindrome (2313642463132).
The spelling of 1211331132011 in words is "one trillion, two hundred eleven billion, three hundred thirty-one million, one hundred thirty-two thousand, eleven".
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