121134010014133 has 4 divisors (see below), whose sum is σ = 126400706101728. Its totient is φ = 115867313926540.

The previous prime is 121134010014131. The next prime is 121134010014163. The reversal of 121134010014133 is 331410010431121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121134010014133 - 2¹ = 121134010014131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121134010014098 and 121134010014107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121134010014131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2633348043763 + ... + 2633348043808.

It is an arithmetic number, because the mean of its divisors is an integer number (31600176525432).

Almost surely, 2^{121134010014133} is an apocalyptic number.

It is an amenable number.

121134010014133 is a deficient number, since it is larger than the sum of its proper divisors (5266696087595).

121134010014133 is an equidigital number, since it uses as much as digits as its factorization.

121134010014133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5266696087594.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 121134010014133 its reverse (331410010431121), we get a palindrome (452544020445254).

The spelling of 121134010014133 in words is "one hundred twenty-one trillion, one hundred thirty-four billion, ten million, fourteen thousand, one hundred thirty-three".