12113413320013 has 2 divisors, whose sum is σ = 12113413320014. Its totient is φ = 12113413320012.

The previous prime is 12113413319941. The next prime is 12113413320149. The reversal of 12113413320013 is 31002331431121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11290695386569 + 822717933444 = 3360163^2 + 907038^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12113413320013 is a prime.

It is a super-2 number, since 2×12113413320013² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12113413320013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113413326013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056706660006 + 6056706660007.

It is an arithmetic number, because the mean of its divisors is an integer number (6056706660007).

Almost surely, 2^{12113413320013} is an apocalyptic number.

It is an amenable number.

12113413320013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113413320013 is an equidigital number, since it uses as much as digits as its factorization.

12113413320013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12113413320013 its reverse (31002331431121), we get a palindrome (43115744751134).

It can be divided in two parts, 1211341 and 3320013, that added together give a palindrome (4531354).

The spelling of 12113413320013 in words is "twelve trillion, one hundred thirteen billion, four hundred thirteen million, three hundred twenty thousand, thirteen".