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1211342429981 is a prime number
BaseRepresentation
bin10001101000001001101…
…000101001111100011101
311021210200112111020211202
4101220021220221330131
5124321312130224411
62324252200125245
7153342123524015
oct21501150517435
94253615436752
101211342429981
11427800249672
12176924166825
138a2c9447a38
14428b4a94c45
152179a86a83b
hex11a09a29f1d

1211342429981 has 2 divisors, whose sum is σ = 1211342429982. Its totient is φ = 1211342429980.

The previous prime is 1211342429971. The next prime is 1211342430007. The reversal of 1211342429981 is 1899242431121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1145349444100 + 65992985881 = 1070210^2 + 256891^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211342429981 - 210 = 1211342428957 is a prime.

It is a super-2 number, since 2×12113424299812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211342429971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605671214990 + 605671214991.

It is an arithmetic number, because the mean of its divisors is an integer number (605671214991).

Almost surely, 21211342429981 is an apocalyptic number.

It is an amenable number.

1211342429981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211342429981 is an equidigital number, since it uses as much as digits as its factorization.

1211342429981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 47.

The spelling of 1211342429981 in words is "one trillion, two hundred eleven billion, three hundred forty-two million, four hundred twenty-nine thousand, nine hundred eighty-one".