Base | Representation |
---|---|
bin | 10001101000001001101… |
… | …000101001111100110111 |
3 | 11021210200112111020212201 |
4 | 101220021220221330313 |
5 | 124321312130230012 |
6 | 2324252200125331 |
7 | 153342123524053 |
oct | 21501150517467 |
9 | 4253615436781 |
10 | 1211342430007 |
11 | 427800249696 |
12 | 176924166847 |
13 | 8a2c9447a58 |
14 | 428b4a94c63 |
15 | 2179a86a857 |
hex | 11a09a29f37 |
1211342430007 has 2 divisors, whose sum is σ = 1211342430008. Its totient is φ = 1211342430006.
The previous prime is 1211342429981. The next prime is 1211342430013. The reversal of 1211342430007 is 7000342431121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211342430007 - 223 = 1211334041399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211342410007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605671215003 + 605671215004.
It is an arithmetic number, because the mean of its divisors is an integer number (605671215004).
Almost surely, 21211342430007 is an apocalyptic number.
1211342430007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211342430007 is an equidigital number, since it uses as much as digits as its factorization.
1211342430007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1211342430007 its reverse (7000342431121), we get a palindrome (8211684861128).
The spelling of 1211342430007 in words is "one trillion, two hundred eleven billion, three hundred forty-two million, four hundred thirty thousand, seven".
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