Base | Representation |
---|---|
bin | 111000011010000101… |
… | …0110000101000000100 |
3 | 102120200001121001012012 |
4 | 1300310022300220010 |
5 | 3441040341221012 |
6 | 131352012513352 |
7 | 11515551506120 |
oct | 1606412605004 |
9 | 376601531165 |
10 | 121134320132 |
11 | 47411190681 |
12 | 1b58777b858 |
13 | b5661c3507 |
14 | 5c11c5a580 |
15 | 323e86a622 |
hex | 1c342b0a04 |
121134320132 has 24 divisors (see below), whose sum is σ = 242276012160. Its totient is φ = 51913128960.
The previous prime is 121134320123. The next prime is 121134320141. The reversal of 121134320132 is 231023431121.
It is an interprime number because it is at equal distance from previous prime (121134320123) and next prime (121134320141).
It is a junction number, because it is equal to n+sod(n) for n = 121134320098 and 121134320107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1739969 + ... + 1808247.
It is an arithmetic number, because the mean of its divisors is an integer number (10094833840).
Almost surely, 2121134320132 is an apocalyptic number.
It is an amenable number.
121134320132 is an abundant number, since it is smaller than the sum of its proper divisors (121141692028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121134320132 is a wasteful number, since it uses less digits than its factorization.
121134320132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131651 (or 131649 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 121134320132 its reverse (231023431121), we get a palindrome (352157751253).
The spelling of 121134320132 in words is "one hundred twenty-one billion, one hundred thirty-four million, three hundred twenty thousand, one hundred thirty-two".
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