12113434303 has 4 divisors (see below), whose sum is σ = 12825989280. Its totient is φ = 11400879328.

The previous prime is 12113434273. The next prime is 12113434327. The reversal of 12113434303 is 30343431121.

12113434303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12113434303 - 2⁹ = 12113433791 is a prime.

It is a super-2 number, since 2×12113434303² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113434393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356277463 + ... + 356277496.

It is an arithmetic number, because the mean of its divisors is an integer number (3206497320).

Almost surely, 2^12113434303 is an apocalyptic number.

12113434303 is a deficient number, since it is larger than the sum of its proper divisors (712554977).

12113434303 is an equidigital number, since it uses as much as digits as its factorization.

12113434303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 712554976.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12113434303 its reverse (30343431121), we get a palindrome (42456865424).

The spelling of 12113434303 in words is "twelve billion, one hundred thirteen million, four hundred thirty-four thousand, three hundred three".