12114019 has 2 divisors, whose sum is σ = 12114020. Its totient is φ = 12114018.

The previous prime is 12114017. The next prime is 12114049. The reversal of 12114019 is 91041121.

12114019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12114019 - 2¹ = 12114017 is a prime.

It is a super-3 number, since 3×12114019³ (a number of 22 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12114017, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12113987 and 12114005.

It is not a weakly prime, because it can be changed into another prime (12114017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057009 + 6057010.

It is an arithmetic number, because the mean of its divisors is an integer number (6057010).

Almost surely, 2^12114019 is an apocalyptic number.

12114019 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114019 is an equidigital number, since it uses as much as digits as its factorization.

12114019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

The square root of 12114019 is about 3480.5199324239. The cubic root of 12114019 is about 229.6656705217.

The spelling of 12114019 in words is "twelve million, one hundred fourteen thousand, nineteen".