Base | Representation |
---|---|
bin | 10001101000001101001… |
… | …100000001000000100111 |
3 | 11021210211200122022021012 |
4 | 101220031030001000213 |
5 | 124321422404444033 |
6 | 2324302125412435 |
7 | 153343446240233 |
oct | 21501514010047 |
9 | 4253750568235 |
10 | 1211402031143 |
11 | 427830957927 |
12 | 17694010a11b |
13 | 8a3088b52b5 |
14 | 428bc96b5c3 |
15 | 217a0be0248 |
hex | 11a0d301027 |
1211402031143 has 4 divisors (see below), whose sum is σ = 1211763971160. Its totient is φ = 1211040091128.
The previous prime is 1211402031139. The next prime is 1211402031209. The reversal of 1211402031143 is 3411302041121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1211402031143 - 22 = 1211402031139 is a prime.
It is a super-3 number, since 3×12114020311433 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211402031113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180964988 + ... + 180971681.
It is an arithmetic number, because the mean of its divisors is an integer number (302940992790).
Almost surely, 21211402031143 is an apocalyptic number.
1211402031143 is a deficient number, since it is larger than the sum of its proper divisors (361940017).
1211402031143 is an equidigital number, since it uses as much as digits as its factorization.
1211402031143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 361940016.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1211402031143 its reverse (3411302041121), we get a palindrome (4622704072264).
The spelling of 1211402031143 in words is "one trillion, two hundred eleven billion, four hundred two million, thirty-one thousand, one hundred forty-three".
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