Base | Representation |
---|---|
bin | 1011000001001000100011… |
… | …0001100000010011001101 |
3 | 1120220002121121222022100000 |
4 | 2300102020301200103031 |
5 | 3041434140212002303 |
6 | 41433050345354513 |
7 | 2360133515610450 |
oct | 260221061402315 |
9 | 46802547868300 |
10 | 12114102453453 |
11 | 3950620025a10 |
12 | 1437964498a39 |
13 | 69b47cb00630 |
14 | 2dc47b985497 |
15 | 1601b0279da3 |
hex | b0488c604cd |
12114102453453 has 192 divisors, whose sum is σ = 24930795681792. Its totient is φ = 5673863220480.
The previous prime is 12114102453451. The next prime is 12114102453463. The reversal of 12114102453453 is 35435420141121.
12114102453453 is a `hidden beast` number, since 1 + 2 + 1 + 14 + 102 + 4 + 534 + 5 + 3 = 666.
It is not a de Polignac number, because 12114102453453 - 21 = 12114102453451 is a prime.
It is a super-3 number, since 3×121141024534533 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12114102453451) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 9880351 + ... + 11038547.
It is an arithmetic number, because the mean of its divisors is an integer number (129847894176).
Almost surely, 212114102453453 is an apocalyptic number.
12114102453453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12114102453453 is an abundant number, since it is smaller than the sum of its proper divisors (12816693228339).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12114102453453 is a wasteful number, since it uses less digits than its factorization.
12114102453453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1158286 (or 1158274 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 12114102453453 its reverse (35435420141121), we get a palindrome (47549522594574).
The spelling of 12114102453453 in words is "twelve trillion, one hundred fourteen billion, one hundred two million, four hundred fifty-three thousand, four hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •