Search a number
-
+
121141212 = 22370114401
BaseRepresentation
bin1110011100001…
…11011111011100
322102221121111120
413032013133130
5222003004322
620004250540
73000453243
oct716073734
9272847446
10121141212
1162421205
12346a0a50
131c1364ba
141213595a
15a97da5c
hex73877dc

121141212 has 24 divisors (see below), whose sum is σ = 283085712. Its totient is φ = 40320000.

The previous prime is 121141171. The next prime is 121141217. The reversal of 121141212 is 212141121.

It is a super-3 number, since 3×1211412123 (a number of 25 digits) contains 333 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 121141191 and 121141200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121141217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1212 + ... + 15612.

It is an arithmetic number, because the mean of its divisors is an integer number (11795238).

Almost surely, 2121141212 is an apocalyptic number.

121141212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

121141212 is an abundant number, since it is smaller than the sum of its proper divisors (161944500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121141212 is a wasteful number, since it uses less digits than its factorization.

121141212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15109 (or 15107 counting only the distinct ones).

The product of its digits is 32, while the sum is 15.

The square root of 121141212 is about 11006.4168556347. The cubic root of 121141212 is about 494.8010791377.

Adding to 121141212 its reverse (212141121), we get a palindrome (333282333).

Subtracting 121141212 from its reverse (212141121), we obtain a palindrome (90999909).

The spelling of 121141212 in words is "one hundred twenty-one million, one hundred forty-one thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 701 1402 2103 2804 4206 8412 14401 28802 43203 57604 86406 172812 10095101 20190202 30285303 40380404 60570606 121141212