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1211430022003 = 9712488969299
BaseRepresentation
bin10001101000001110110…
…110110010101101110011
311021210220122022101111201
4101220032312302231303
5124322002041201003
62324305005352031
7153344236200235
oct21501666625563
94253818271451
101211430022003
11427845735873
12176949568617
138a311635936
14428c2576255
15217a33bdb1d
hex11a0edb2b73

1211430022003 has 4 divisors (see below), whose sum is σ = 1223918991400. Its totient is φ = 1198941052608.

The previous prime is 1211430021943. The next prime is 1211430022043. The reversal of 1211430022003 is 3002200341121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1211430022003 - 213 = 1211430013811 is a prime.

It is a super-3 number, since 3×12114300220033 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1211430022043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6244484553 + ... + 6244484746.

It is an arithmetic number, because the mean of its divisors is an integer number (305979747850).

Almost surely, 21211430022003 is an apocalyptic number.

1211430022003 is a deficient number, since it is larger than the sum of its proper divisors (12488969397).

1211430022003 is an equidigital number, since it uses as much as digits as its factorization.

1211430022003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12488969396.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1211430022003 its reverse (3002200341121), we get a palindrome (4213630363124).

The spelling of 1211430022003 in words is "one trillion, two hundred eleven billion, four hundred thirty million, twenty-two thousand, three".

Divisors: 1 97 12488969299 1211430022003