Base | Representation |
---|---|
bin | 10001101000001111000… |
… | …011010111111001000000 |
3 | 11021210220212111221111202 |
4 | 101220033003113321000 |
5 | 124322003412220000 |
6 | 2324305204200332 |
7 | 153344306214341 |
oct | 21501703277100 |
9 | 4253825457452 |
10 | 1211433320000 |
11 | 427847588692 |
12 | 17694a6990a8 |
13 | 8a31221bb07 |
14 | 428c2b940c8 |
15 | 217a3820dd5 |
hex | 11a0f0d7e40 |
1211433320000 has 70 divisors (see below), whose sum is σ = 3003961016958. Its totient is φ = 484573312000.
The previous prime is 1211433319991. The next prime is 1211433320029. The reversal of 1211433320000 is 233341121.
It can be written as a sum of positive squares in 5 ways, for example, as 228591084544 + 982842235456 = 478112^2 + 991384^2 .
It is a super-3 number, since 3×12114333200003 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 15102917 + ... + 15182916.
Almost surely, 21211433320000 is an apocalyptic number.
1211433320000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1211433320000 is an abundant number, since it is smaller than the sum of its proper divisors (1792527696958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1211433320000 is an frugal number, since it uses more digits than its factorization.
1211433320000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30285865 (or 30285840 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1211433320000 its reverse (233341121), we get a palindrome (1211666661121).
The spelling of 1211433320000 in words is "one trillion, two hundred eleven billion, four hundred thirty-three million, three hundred twenty thousand".
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