12114343021631 has 2 divisors, whose sum is σ = 12114343021632. Its totient is φ = 12114343021630.

The previous prime is 12114343021589. The next prime is 12114343021633. The reversal of 12114343021631 is 13612034341121.

12114343021631 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12114343021631 - 2¹⁰ = 12114343020607 is a prime.

It is a super-3 number, since 3×12114343021631³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12114343021633, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12114343021633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057171510815 + 6057171510816.

It is an arithmetic number, because the mean of its divisors is an integer number (6057171510816).

Almost surely, 2^{12114343021631} is an apocalyptic number.

12114343021631 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114343021631 is an equidigital number, since it uses as much as digits as its factorization.

12114343021631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 12114343021631 its reverse (13612034341121), we get a palindrome (25726377362752).

The spelling of 12114343021631 in words is "twelve trillion, one hundred fourteen billion, three hundred forty-three million, twenty-one thousand, six hundred thirty-one".