121144440434133 has 24 divisors (see below), whose sum is σ = 175771391725440. Its totient is φ = 74158241850880.

The previous prime is 121144440434131. The next prime is 121144440434159. The reversal of 121144440434133 is 331434044441121.

It is not a de Polignac number, because 121144440434133 - 2¹ = 121144440434131 is a prime.

It is a super-3 number, since 3×121144440434133³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 121144440434091 and 121144440434100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121144440434131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1703968173 + ... + 1704039266.

It is an arithmetic number, because the mean of its divisors is an integer number (7323807988560).

Almost surely, 2^{121144440434133} is an apocalyptic number.

It is an amenable number.

121144440434133 is a deficient number, since it is larger than the sum of its proper divisors (54626951291307).

121144440434133 is a wasteful number, since it uses less digits than its factorization.

121144440434133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3408007517 (or 3408007500 counting only the distinct ones).

The product of its (nonzero) digits is 221184, while the sum is 39.

Adding to 121144440434133 its reverse (331434044441121), we get a palindrome (452578484875254).

The spelling of 121144440434133 in words is "one hundred twenty-one trillion, one hundred forty-four billion, four hundred forty million, four hundred thirty-four thousand, one hundred thirty-three".