Base | Representation |
---|---|
bin | 10001101000110000111… |
… | …001101111010111011001 |
3 | 11021212101110010020221012 |
4 | 101220300321233113121 |
5 | 124324134303020212 |
6 | 2324441412223305 |
7 | 153364343250545 |
oct | 21506071572731 |
9 | 4255343106835 |
10 | 1212001220057 |
11 | 428009101381 |
12 | 176a8890ab35 |
13 | 8a3a2a88954 |
14 | 42938382a25 |
15 | 217d85ec922 |
hex | 11a30e6f5d9 |
1212001220057 has 2 divisors, whose sum is σ = 1212001220058. Its totient is φ = 1212001220056.
The previous prime is 1212001220039. The next prime is 1212001220159. The reversal of 1212001220057 is 7500221002121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1209073977241 + 2927242816 = 1099579^2 + 54104^2 .
It is a cyclic number.
It is not a de Polignac number, because 1212001220057 - 216 = 1212001154521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1212001220557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606000610028 + 606000610029.
It is an arithmetic number, because the mean of its divisors is an integer number (606000610029).
Almost surely, 21212001220057 is an apocalyptic number.
It is an amenable number.
1212001220057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212001220057 is an equidigital number, since it uses as much as digits as its factorization.
1212001220057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 1212001220057 its reverse (7500221002121), we get a palindrome (8712222222178).
The spelling of 1212001220057 in words is "one trillion, two hundred twelve billion, one million, two hundred twenty thousand, fifty-seven".
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