Base | Representation |
---|---|
bin | 111000011100000100… |
… | …1100000100101010111 |
3 | 102120211201020212111222 |
4 | 1300320021200211113 |
5 | 3441204440214033 |
6 | 131402400120555 |
7 | 11520322235003 |
oct | 1607011404527 |
9 | 376751225458 |
10 | 121201101143 |
11 | 474459531a1 |
12 | 1b5a600615b |
13 | b576ca5ac5 |
14 | 5c1aa81703 |
15 | 324565c598 |
hex | 1c38260957 |
121201101143 has 2 divisors, whose sum is σ = 121201101144. Its totient is φ = 121201101142.
The previous prime is 121201101113. The next prime is 121201101157. The reversal of 121201101143 is 341101102121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121201101143 - 28 = 121201100887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121201101103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600550571 + 60600550572.
It is an arithmetic number, because the mean of its divisors is an integer number (60600550572).
Almost surely, 2121201101143 is an apocalyptic number.
121201101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
121201101143 is an equidigital number, since it uses as much as digits as its factorization.
121201101143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 121201101143 its reverse (341101102121), we get a palindrome (462302203264).
The spelling of 121201101143 in words is "one hundred twenty-one billion, two hundred one million, one hundred one thousand, one hundred forty-three".
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