Base | Representation |
---|---|
bin | 10001101000110001100… |
… | …011101101001000001111 |
3 | 11021212102012211011022102 |
4 | 101220301203231020033 |
5 | 124324200112032233 |
6 | 2324442444105315 |
7 | 153364535616236 |
oct | 21506143551017 |
9 | 4255365734272 |
10 | 1212012220943 |
11 | 428014335517 |
12 | 176a9053523b |
13 | 8a3a513ac54 |
14 | 42939a07b1d |
15 | 217d95721e8 |
hex | 11a318ed20f |
1212012220943 has 2 divisors, whose sum is σ = 1212012220944. Its totient is φ = 1212012220942.
The previous prime is 1212012220919. The next prime is 1212012221011. The reversal of 1212012220943 is 3490222102121.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3490222102121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1212012220943 - 212 = 1212012216847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212012220343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006110471 + 606006110472.
It is an arithmetic number, because the mean of its divisors is an integer number (606006110472).
Almost surely, 21212012220943 is an apocalyptic number.
1212012220943 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212012220943 is an equidigital number, since it uses as much as digits as its factorization.
1212012220943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
The spelling of 1212012220943 in words is "one trillion, two hundred twelve billion, twelve million, two hundred twenty thousand, nine hundred forty-three".
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