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12120164103 = 323603171167
BaseRepresentation
bin10110100100110101…
…10000011100000111
31011021200020010111210
423102122300130013
5144310230222403
65322401102503
7606230460255
oct132232603407
934250203453
1012120164103
11515a575753
122423027a33
1311b2018348
1482d97b5d5
154ae0a9b03
hex2d26b0707

12120164103 has 8 divisors (see below), whose sum is σ = 16160997888. Its totient is φ = 8079719864.

The previous prime is 12120164099. The next prime is 12120164107. The reversal of 12120164103 is 30146102121.

It is an interprime number because it is at equal distance from previous prime (12120164099) and next prime (12120164107).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12120164103 - 22 = 12120164099 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12120164103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120164107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14775 + ... + 156392.

It is an arithmetic number, because the mean of its divisors is an integer number (2020124736).

Almost surely, 212120164103 is an apocalyptic number.

12120164103 is a deficient number, since it is larger than the sum of its proper divisors (4040833785).

12120164103 is a wasteful number, since it uses less digits than its factorization.

12120164103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 194773.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 12120164103 its reverse (30146102121), we get a palindrome (42266266224).

The spelling of 12120164103 in words is "twelve billion, one hundred twenty million, one hundred sixty-four thousand, one hundred three".

Divisors: 1 3 23603 70809 171167 513501 4040054701 12120164103