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121203410000353 is a prime number
BaseRepresentation
bin11011100011101111011110…
…001100101101100111100001
3120220010221012001000010000021
4123203233132030231213201
5111341244040430002403
61105440024453353441
734346441326335202
oct3343573614554741
9526127161003007
10121203410000353
113568a0941a700a
1211716048938881
13528258132c265
1421d03c24095a9
15e02ba38c18bd
hex6e3bde32d9e1

121203410000353 has 2 divisors, whose sum is σ = 121203410000354. Its totient is φ = 121203410000352.

The previous prime is 121203410000273. The next prime is 121203410000429. The reversal of 121203410000353 is 353000014302121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104238954223504 + 16964455776849 = 10209748^2 + 4118793^2 .

It is an emirp because it is prime and its reverse (353000014302121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121203410000353 is a prime.

It is not a weakly prime, because it can be changed into another prime (121203410000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60601705000176 + 60601705000177.

It is an arithmetic number, because the mean of its divisors is an integer number (60601705000177).

Almost surely, 2121203410000353 is an apocalyptic number.

It is an amenable number.

121203410000353 is a deficient number, since it is larger than the sum of its proper divisors (1).

121203410000353 is an equidigital number, since it uses as much as digits as its factorization.

121203410000353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 121203410000353 its reverse (353000014302121), we get a palindrome (474203424302474).

The spelling of 121203410000353 in words is "one hundred twenty-one trillion, two hundred three billion, four hundred ten million, three hundred fifty-three", and thus it is an aban number.