12120433 has 4 divisors (see below), whose sum is σ = 13052788. Its totient is φ = 11188080.

The previous prime is 12120431. The next prime is 12120443. The reversal of 12120433 is 33402121.

It is a happy number.

12120433 is nontrivially palindromic in base 11.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4765489 + 7354944 = 2183^2 + 2712^2 .

It is a cyclic number.

It is not a de Polignac number, because 12120433 - 2¹ = 12120431 is a prime.

It is a super-2 number, since 2×12120433² = 293809792214978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12120431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466158 + ... + 466183.

It is an arithmetic number, because the mean of its divisors is an integer number (3263197).

Almost surely, 2^12120433 is an apocalyptic number.

12120433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12120433 is a deficient number, since it is larger than the sum of its proper divisors (932355).

12120433 is an equidigital number, since it uses as much as digits as its factorization.

12120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 932354.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 12120433 is about 3481.4412245505. The cubic root of 12120433 is about 229.7061970033.

Adding to 12120433 its reverse (33402121), we get a palindrome (45522554).

The spelling of 12120433 in words is "twelve million, one hundred twenty thousand, four hundred thirty-three".