Base | Representation |
---|---|
bin | 10001101000110111100… |
… | …000010111101110100011 |
3 | 11021212200011120222100212 |
4 | 101220313200113232203 |
5 | 124324401133311042 |
6 | 2324500411004335 |
7 | 153400160042663 |
oct | 21506740275643 |
9 | 4255604528325 |
10 | 1212112010147 |
11 | 4280656a2635 |
12 | 176ab9a396ab |
13 | 8a3bca0980c |
14 | 42948d821a3 |
15 | 217e31d4482 |
hex | 11a37817ba3 |
1212112010147 has 2 divisors, whose sum is σ = 1212112010148. Its totient is φ = 1212112010146.
The previous prime is 1212112010099. The next prime is 1212112010149. The reversal of 1212112010147 is 7410102112121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212112010147 is a prime.
Together with 1212112010149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1212112010149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606056005073 + 606056005074.
It is an arithmetic number, because the mean of its divisors is an integer number (606056005074).
Almost surely, 21212112010147 is an apocalyptic number.
1212112010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212112010147 is an equidigital number, since it uses as much as digits as its factorization.
1212112010147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 1212112010147 its reverse (7410102112121), we get a palindrome (8622214122268).
The spelling of 1212112010147 in words is "one trillion, two hundred twelve billion, one hundred twelve million, ten thousand, one hundred forty-seven".
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