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1212112010147 is a prime number
BaseRepresentation
bin10001101000110111100…
…000010111101110100011
311021212200011120222100212
4101220313200113232203
5124324401133311042
62324500411004335
7153400160042663
oct21506740275643
94255604528325
101212112010147
114280656a2635
12176ab9a396ab
138a3bca0980c
1442948d821a3
15217e31d4482
hex11a37817ba3

1212112010147 has 2 divisors, whose sum is σ = 1212112010148. Its totient is φ = 1212112010146.

The previous prime is 1212112010099. The next prime is 1212112010149. The reversal of 1212112010147 is 7410102112121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1212112010147 is a prime.

Together with 1212112010149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1212112010149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606056005073 + 606056005074.

It is an arithmetic number, because the mean of its divisors is an integer number (606056005074).

Almost surely, 21212112010147 is an apocalyptic number.

1212112010147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212112010147 is an equidigital number, since it uses as much as digits as its factorization.

1212112010147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 1212112010147 its reverse (7410102112121), we get a palindrome (8622214122268).

The spelling of 1212112010147 in words is "one trillion, two hundred twelve billion, one hundred twelve million, ten thousand, one hundred forty-seven".