Base | Representation |
---|---|
bin | 10001101000110111111… |
… | …110111001010011110110 |
3 | 11021212200201122111212121 |
4 | 101220313332321103312 |
5 | 124324410210341042 |
6 | 2324501254310154 |
7 | 153400315051033 |
oct | 21506776712366 |
9 | 4255621574777 |
10 | 1212120012022 |
11 | 42806a168557 |
12 | 176b0065835a |
13 | 8a3c157ba5a |
14 | 4294a06638a |
15 | 217e3c65367 |
hex | 11a37fb94f6 |
1212120012022 has 8 divisors (see below), whose sum is σ = 1820490287256. Its totient is φ = 605289916272.
The previous prime is 1212120012011. The next prime is 1212120012023. The reversal of 1212120012022 is 2202100212121.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1212120011987 and 1212120012005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1212120012023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385042903 + ... + 385046050.
It is an arithmetic number, because the mean of its divisors is an integer number (227561285907).
Almost surely, 21212120012022 is an apocalyptic number.
1212120012022 is a deficient number, since it is larger than the sum of its proper divisors (608370275234).
1212120012022 is an equidigital number, since it uses as much as digits as its factorization.
1212120012022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 770089742.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1212120012022 its reverse (2202100212121), we get a palindrome (3414220224143).
The spelling of 1212120012022 in words is "one trillion, two hundred twelve billion, one hundred twenty million, twelve thousand, twenty-two".
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