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1212132132 = 2232193734751
BaseRepresentation
bin100100000111111…
…1010101100100100
310010110211200200200
41020033322230210
54440301212012
6320140110500
742015644631
oct11017725444
93113750620
101212132132
115722428a2
12299b35430
13164181663
14b6dab188
15716353dc
hex483fab24

1212132132 has 72 divisors (see below), whose sum is σ = 3234591360. Its totient is φ = 381672000.

The previous prime is 1212132121. The next prime is 1212132143. The reversal of 1212132132 is 2312312121.

It is an interprime number because it is at equal distance from previous prime (1212132121) and next prime (1212132143).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a nude number because it is divisible by every one of its digits.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 252757 + ... + 257507.

It is an arithmetic number, because the mean of its divisors is an integer number (44924880).

Almost surely, 21212132132 is an apocalyptic number.

1212132132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1212132132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1617295680).

1212132132 is an abundant number, since it is smaller than the sum of its proper divisors (2022459228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1212132132 is a wasteful number, since it uses less digits than its factorization.

1212132132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5153 (or 5148 counting only the distinct ones).

The product of its digits is 144, while the sum is 18.

The square root of 1212132132 is about 34815.6880156058. The cubic root of 1212132132 is about 1066.2277660886.

Adding to 1212132132 its reverse (2312312121), we get a palindrome (3524444253).

It can be divided in two parts, 12121 and 32132, that added together give a triangular number (44253 = T297).

The spelling of 1212132132 in words is "one billion, two hundred twelve million, one hundred thirty-two thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 9 12 18 19 36 38 57 76 114 171 228 342 373 684 746 1119 1492 2238 3357 4476 4751 6714 7087 9502 13428 14174 14253 19004 21261 28348 28506 42522 42759 57012 63783 85044 85518 90269 127566 171036 180538 255132 270807 361076 541614 812421 1083228 1624842 1772123 3249684 3544246 5316369 7088492 10632738 15949107 21265476 31898214 33670337 63796428 67340674 101011011 134681348 202022022 303033033 404044044 606066066 1212132132