Base | Representation |
---|---|
bin | 10001101000111000110… |
… | …000110101111001000111 |
3 | 11021212201122021201100222 |
4 | 101220320300311321013 |
5 | 124324422033331343 |
6 | 2324502443054555 |
7 | 153400534252445 |
oct | 21507060657107 |
9 | 4255648251328 |
10 | 1212133105223 |
11 | 4280765a0687 |
12 | 176b04b1145b |
13 | 8a3c41b4501 |
14 | 4294bab3b95 |
15 | 217e4e9ea68 |
hex | 11a38c35e47 |
1212133105223 has 2 divisors, whose sum is σ = 1212133105224. Its totient is φ = 1212133105222.
The previous prime is 1212133105181. The next prime is 1212133105259. The reversal of 1212133105223 is 3225013312121.
It is a strong prime.
It is an emirp because it is prime and its reverse (3225013312121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1212133105223 - 218 = 1212132843079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1212133105192 and 1212133105201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212133105423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606066552611 + 606066552612.
It is an arithmetic number, because the mean of its divisors is an integer number (606066552612).
Almost surely, 21212133105223 is an apocalyptic number.
1212133105223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212133105223 is an equidigital number, since it uses as much as digits as its factorization.
1212133105223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 1212133105223 its reverse (3225013312121), we get a palindrome (4437146417344).
The spelling of 1212133105223 in words is "one trillion, two hundred twelve billion, one hundred thirty-three million, one hundred five thousand, two hundred twenty-three".
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