Base | Representation |
---|---|
bin | 10001101000111101010… |
… | …110100011111101111111 |
3 | 11021212221000011120021202 |
4 | 101220331112203331333 |
5 | 124330101241232033 |
6 | 2324514233250115 |
7 | 153402460600325 |
oct | 21507526437577 |
9 | 4255830146252 |
10 | 1212210102143 |
11 | 4281060005a7 |
12 | 176b2686393b |
13 | 8a407132a11 |
14 | 42957dd7d15 |
15 | 217ebb0d8e8 |
hex | 11a3d5a3f7f |
1212210102143 has 2 divisors, whose sum is σ = 1212210102144. Its totient is φ = 1212210102142.
The previous prime is 1212210102113. The next prime is 1212210102157. The reversal of 1212210102143 is 3412010122121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1212210102143 - 26 = 1212210102079 is a prime.
It is a super-3 number, since 3×12122101021433 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212210102113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606105051071 + 606105051072.
It is an arithmetic number, because the mean of its divisors is an integer number (606105051072).
Almost surely, 21212210102143 is an apocalyptic number.
1212210102143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212210102143 is an equidigital number, since it uses as much as digits as its factorization.
1212210102143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1212210102143 its reverse (3412010122121), we get a palindrome (4624220224264).
The spelling of 1212210102143 in words is "one trillion, two hundred twelve billion, two hundred ten million, one hundred two thousand, one hundred forty-three".
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