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1212210102113 is a prime number
BaseRepresentation
bin10001101000111101010…
…110100011111101100001
311021212221000011120020122
4101220331112203331201
5124330101241231423
62324514233250025
7153402460600253
oct21507526437541
94255830146218
101212210102113
1142810600057a
12176b26863915
138a4071329ba
1442957dd7cd3
15217ebb0d8c8
hex11a3d5a3f61

1212210102113 has 2 divisors, whose sum is σ = 1212210102114. Its totient is φ = 1212210102112.

The previous prime is 1212210102109. The next prime is 1212210102143. The reversal of 1212210102113 is 3112010122121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 829899136144 + 382310965969 = 910988^2 + 618313^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212210102113 - 22 = 1212210102109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212210102091 and 1212210102100.

It is not a weakly prime, because it can be changed into another prime (1212210102143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606105051056 + 606105051057.

It is an arithmetic number, because the mean of its divisors is an integer number (606105051057).

Almost surely, 21212210102113 is an apocalyptic number.

It is an amenable number.

1212210102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212210102113 is an equidigital number, since it uses as much as digits as its factorization.

1212210102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1212210102113 its reverse (3112010122121), we get a palindrome (4324220224234).

The spelling of 1212210102113 in words is "one trillion, two hundred twelve billion, two hundred ten million, one hundred two thousand, one hundred thirteen".